# If the log (x) = -7.65, how do you find x?

Damien Horton 2022-07-28 Answered
If the $\mathrm{log}\left(x\right)=-7.65$, how do you find x?
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## Answers (2)

Shelby Strong
Answered 2022-07-29 Author has 9 answers
remember: $\mathrm{log}\left(x\right)$ means ${\mathrm{log}}_{10}\left(x\right)$
log property: ${a}^{{\mathrm{log}}_{10}\left(x\right)}=x$
${\mathrm{log}}_{10}\left(x\right)=-7.65$
${10}^{{\mathrm{log}}_{10}\left(x\right)}={10}^{-7.65}$
$x={10}^{-7.65}$
x=0.000000023872 or $2.23872×{10}^{-8}$
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Makena Preston
Answered 2022-07-30 Author has 3 answers
$1.\mathrm{log}\left(x\right)=-7.65$
$2.{10}^{\mathrm{log}\left(x\right)}={10}^{-7.65}$ ---> when 10 to the powerof log, log and 10 cancel each other.
$3.X={10}^{-7.65}$
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