beatricalwu
2022-07-28
Answered

Find $L=\underset{n\to \mathrm{\infty}}{lim}\frac{4n+1}{2n+1}$. then determine ${\u03f5}_{n}=L-{x}_{n}$ and find $\underset{n\to \mathrm{\infty}}{lim}{\u03f5}_{n}$.

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Kendrick Jacobs

Answered 2022-07-29
Author has **16** answers

find $=4/2\Rightarrow L=2$

then determine ${\u03f5}_{n}=\frac{1}{2}-{x}_{n}$ and find

$=\underset{n\to \mathrm{\infty}}{lim}2-\underset{n\to \mathrm{\infty}}{lim}{x}_{n}=2-\underset{n\to \mathrm{\infty}}{lim}{x}_{n}$

then determine ${\u03f5}_{n}=\frac{1}{2}-{x}_{n}$ and find

$=\underset{n\to \mathrm{\infty}}{lim}2-\underset{n\to \mathrm{\infty}}{lim}{x}_{n}=2-\underset{n\to \mathrm{\infty}}{lim}{x}_{n}$

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