Find the solution of the given initial value problem.

$t{y}^{\prime}+2y=\mathrm{sin}t,y(3.14/2)=1,t>0$

$t{y}^{\prime}+2y=\mathrm{sin}t,y(3.14/2)=1,t>0$

Emmanuel Pace
2022-07-26
Answered

Find the solution of the given initial value problem.

$t{y}^{\prime}+2y=\mathrm{sin}t,y(3.14/2)=1,t>0$

$t{y}^{\prime}+2y=\mathrm{sin}t,y(3.14/2)=1,t>0$

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