Baladdaa9
2022-07-25
Answered

Find $\frac{dy}{dx}$ for $y={x}^{-2/9}$

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i4epdp

Answered 2022-07-26
Author has **12** answers

$y={x}^{-2/9}$

Use power rule which is $\frac{d}{dx}[{x}^{n}]=n{x}^{n-1}$

So, $\frac{dy}{dx}=-\frac{2}{9}{x}^{-11/9}$ (I just moved ${x}^{-11/9}$ to the denominator which made it positive 11/9).

Use power rule which is $\frac{d}{dx}[{x}^{n}]=n{x}^{n-1}$

So, $\frac{dy}{dx}=-\frac{2}{9}{x}^{-11/9}$ (I just moved ${x}^{-11/9}$ to the denominator which made it positive 11/9).

on2t1inf8b

Answered 2022-07-27
Author has **4** answers

using $[{x}^{n}{]}^{\prime}=n{x}^{n-1}$

we have:

$\frac{dy}{dx}=-\frac{2}{9}{x}^{-\frac{2}{9}-1}=-\frac{2}{9}{x}^{-\frac{11}{9}}$

we have:

$\frac{dy}{dx}=-\frac{2}{9}{x}^{-\frac{2}{9}-1}=-\frac{2}{9}{x}^{-\frac{11}{9}}$

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