# Simplify. Write the answer as a single term without negative exponents. (c^(-7) +d^(-8))^(-1)

Simplify. Write the answer as a single term without negative exponents.
$\left({c}^{-}7+{d}^{-8}{\right)}^{-1}$
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Makenna Lin
Given that
$\left({c}^{-}7+{d}^{-8}{\right)}^{-1}$
for simplifying this
$\frac{1}{{c}^{7}+{d}^{-8}}=\frac{1}{\frac{1}{{c}^{7}}+\frac{1}{{d}^{8}}}\phantom{\rule{0ex}{0ex}}=\frac{1}{\frac{{c}^{7}+{d}^{8}}{{c}^{7}\cdot {d}^{8}}}\phantom{\rule{0ex}{0ex}}=\frac{{c}^{7}{d}^{8}}{{c}^{7}+{d}^{8}}$