# 3/(2y)-3/(2y+4)=

$\frac{3}{2y}﻿-\frac{3}{2y+4}=$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

phravincegrln2
$\frac{3}{2y}﻿-\frac{3}{2y+4}=\frac{6y+12-6y}{2y\left(2y+4\right)}=\frac{12}{2y\left(2y+4\right)}=\frac{6}{y\left(2y+4\right)}=\frac{3}{{y}^{2}+2y}$