If a ball is throwndirectly upward with a velocity of 40ft/s, its height (in feet)after t seconds is given by y=40t-16t^2. What is the maximum heightattained by the ball?
Tamara Bryan 2022-07-25Answered
If a ball is throwndirectly upward with a velocity of 40ft/s, its height (in feet)after t seconds is given by . What is the maximum heightattained by the ball?
take the derivative y' = 40 -32t set y' = 0 0 = 40 -32t minus 40 to both side -40 =-32t divide -32 to both side 5/4 =t plug in t in the oringal function simplify y(5/4) = 50 - 25 = 25