Apply the first fundamental theorem of calculus to each function over the interval indicated. f(x)=(3x)/(x^2 +1) over [-1, 1]

Paxton Hoffman 2022-07-26 Answered
Apply the first fundamental theorem of calculus to each function over the interval indicated.
f ( x ) = 3 x x 2 + 1 over [-1,1]
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Answers (1)

Reinfarktq6
Answered 2022-07-27 Author has 18 answers
f ( x ) = 3 x x 2 + 1 over [-1,1]
1 1 3 x x 2 + 1 d x = 3 1 1 x x 2 + 1 d x = 3 2 2 2 1 u d u = 0
remember a a f ( x ) d x = 0
x 2 + 1 = u
x = 1 u = 2
2xdx=du
x = 1 u = 2
xdx=du/2
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