# a cylindrical tank of height equal to twice the diameter of its base can hold 10 liters (1L=1000 cm^3) of water. another cylindrical container with the same capacity has its height equal to three times the diameter of its base. find the ratio of the amount of aluminum required for making the two containers, including the covers.

A cylindrical tank of height equal to twice the diameter of its base can hold 10 liters (1L=1000 c${m}^{3}$) of water. another cylindrical container with the same capacity has its height equal to three times the diameter of its base. find the ratio of the amount of aluminum required for making the two containers, including the covers.
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

emerhelienapj
volume of cylinder = $\pi ×{R}^{2}×H$
since H = 2D=4R
10litres= $\pi ×{R}^{2}×4×R$
rearranging:
$\frac{2.5}{\pi }={R}^{\frac{1}{3}}$
R= 9.267 cm
surface area = $2\left(ends\right)×\pi ×{R}^{2}$Copyright ©2011-2012 CUI WEI. All Rights Reserved. + (circumference x height)
similarly for the 3 x height
$10÷6÷\pi ={R}^{\frac{1}{3}}$