a cylindrical tank of height equal to twice the diameter of its base can hold 10 liters (1L=1000 cm^3) of water. another cylindrical container with the same capacity has its height equal to three times the diameter of its base. find the ratio of the amount of aluminum required for making the two containers, including the covers.

Question

A cylindrical tank of height equal to twice the diameter of its base can hold 10 liters (1L=1000 c

m^{3}

) of water. another cylindrical container with the same capacity has its height equal to three times the diameter of its base. find the ratio of the amount of aluminum required for making the two containers, including the covers.

Answer 1

volume of cylinder =

π \times R^{2} \times H

since H = 2D=4R
10litres=

π \times R^{2} \times 4 \times R

rearranging:

\frac{2.5}{π} = R^{\frac{1}{3}}

R= 9.267 cm
surface area =

2 (e n d s) \times π \times R^{2}

10 \div 6 \div π = R^{\frac{1}{3}}

Answers (1)

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