# Find the value of k so that the graph of 21y+kx=4 and the line containing the point 5,-8 adn 2,4 are parallel.

Find the value of k so that the graph of 21y+kx=4 and the line containing the point 5,-8 adn 2,4 are parallel.
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kamphundg4
what you would have to do is find the slope of the linecontaining the points (5,-8) and (2,4).
so that would be:
$m=\left({y}_{2}-{y}_{1}\right)÷\left({x}_{2}-{x}_{1}\right)=\left(4-\left(-8\right)\right)/\left(2-5\right)=-4$
since it is parallel to the given equation of the line, thenthey would have the same slope.
k= -4 and your equation would be:
21y-4x= 4