1. solve the equation and check ur solution. 2/(x-4)(x-2) = 1/x-4 + 2/x-2 2. simplyfy the expression 3x^(1/3) - x^(-2/3) / 3x^(-2/3) 3. simplyfy the comlex fraction. x(under squareroot) - 1/ 2x(x under square root) / x(x under squareroot).

kominis3q 2022-07-26 Answered
1. solve the equation and check ur solution. 2/(x-4)(x-2) = 1/x-4 + 2/x-2
2. simplyfy the expression 3 x 1 / 3 x 2 / 3 / 3 x 2 / 3
3. simplyfy the comlex fraction. x(under squareroot) - 1/ 2x(x under square root) / x(x under squareroot).
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Answers (1)

lelapem
Answered 2022-07-27 Author has 12 answers
1. 2 ( x 4 ) ( x 2 ) = 1 x 4 + 2 x 2
Get a common denominator on the right side of the equation
2 ( x 4 ) ( x 2 ) = ( 1 x 4 ) ( x 2 x 2 ) + ( 2 x 2 ) ( x 4 x 4 )
Simplify
2 ( x 4 ) ( x 2 ) = x 2 ( x 4 ) ( x 2 ) + 2 ( x 4 ) ( x 4 ) ( x 2 )
Now the denominators will all cancel if you multiply bothsides of the equation by (x-4)(x-2). Just be sure your answer does not include 4 or 2 because that would make your originaldenominator 0. You are left to solve:
2 = x - 2 + 2(x-4)
2. If you have a negative exponent in thedenominator of your fraction, it can be brought up to the numerator as a positive exponent. So the original problem becomes x 2 3 ( 3 x 1 3 x 2 3 ) 3 o depending on whether there were parentheses around the 3x in the denominator. Now just multiply and use yourexponent rules.
3. x 1 2 x x = 1 x ( x 1 2 x ) Multiply through and simplify.
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