2. simplyfy the expression $3{x}^{1/3}-{x}^{-2/3}/3{x}^{-2/3}$

3. simplyfy the comlex fraction. x(under squareroot) - 1/ 2x(x under square root) / x(x under squareroot).

kominis3q
2022-07-26
Answered

1. solve the equation and check ur solution. 2/(x-4)(x-2) = 1/x-4 + 2/x-2

2. simplyfy the expression $3{x}^{1/3}-{x}^{-2/3}/3{x}^{-2/3}$

3. simplyfy the comlex fraction. x(under squareroot) - 1/ 2x(x under square root) / x(x under squareroot).

2. simplyfy the expression $3{x}^{1/3}-{x}^{-2/3}/3{x}^{-2/3}$

3. simplyfy the comlex fraction. x(under squareroot) - 1/ 2x(x under square root) / x(x under squareroot).

You can still ask an expert for help

lelapem

Answered 2022-07-27
Author has **12** answers

1. $\frac{2}{(x-4)(x-2)}=\frac{1}{x-4}+\frac{2}{x-2}$

Get a common denominator on the right side of the equation

$\frac{2}{(x-4)(x-2)}=(\frac{1}{x-4})(\frac{x-2}{x-2})+(\frac{2}{x-2})(\frac{x-4}{x-4})$

Simplify

$\frac{2}{(x-4)(x-2)}=\frac{x-2}{(x-4)(x-2)}+\frac{2(x-4)}{(x-4)(x-2)}$

Now the denominators will all cancel if you multiply bothsides of the equation by (x-4)(x-2). Just be sure your answer does not include 4 or 2 because that would make your originaldenominator 0. You are left to solve:

2 = x - 2 + 2(x-4)

2. If you have a negative exponent in thedenominator of your fraction, it can be brought up to the numerator as a positive exponent. So the original problem becomes $\frac{{x}^{\frac{2}{3}(3{x}^{\frac{1}{3}}-{x}^{\frac{-2}{3}})}}{3}$ o depending on whether there were parentheses around the 3x in the denominator. Now just multiply and use yourexponent rules.

3. $\frac{\sqrt{x}-\frac{1}{2\sqrt{x}}}{\sqrt{x}}=\frac{1}{\sqrt{x}}(\sqrt{x}-\frac{1}{2\sqrt{x}})$ Multiply through and simplify.

Get a common denominator on the right side of the equation

$\frac{2}{(x-4)(x-2)}=(\frac{1}{x-4})(\frac{x-2}{x-2})+(\frac{2}{x-2})(\frac{x-4}{x-4})$

Simplify

$\frac{2}{(x-4)(x-2)}=\frac{x-2}{(x-4)(x-2)}+\frac{2(x-4)}{(x-4)(x-2)}$

Now the denominators will all cancel if you multiply bothsides of the equation by (x-4)(x-2). Just be sure your answer does not include 4 or 2 because that would make your originaldenominator 0. You are left to solve:

2 = x - 2 + 2(x-4)

2. If you have a negative exponent in thedenominator of your fraction, it can be brought up to the numerator as a positive exponent. So the original problem becomes $\frac{{x}^{\frac{2}{3}(3{x}^{\frac{1}{3}}-{x}^{\frac{-2}{3}})}}{3}$ o depending on whether there were parentheses around the 3x in the denominator. Now just multiply and use yourexponent rules.

3. $\frac{\sqrt{x}-\frac{1}{2\sqrt{x}}}{\sqrt{x}}=\frac{1}{\sqrt{x}}(\sqrt{x}-\frac{1}{2\sqrt{x}})$ Multiply through and simplify.

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