There were 855 major league baseball players in 2012 and their mean salary was m = 3.44 million dollars with standard deviation s = 4.70 million dolla

There were 855 major league baseball players in 2012 and their mean salary was $m=3.44$ million dollars with standard deviation $s=4.70$ million dollars.If we take random samples of size $n=30$ players and calculate the mean salary, in millions of dollars, of each sample, describe the shape, center, and standard error of the distribution of sample means.
You can still ask an expert for help

Want to know more about Sampling distributions?

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

irwchh

Step 1
If a sample is drawn =, then the sample will follow normal distribution because all the sampling distributions approximately follows the normal distribution with mean, m and standard deviation, $\sqrt{n}$.
Therefore, the shape of distribution is approximately symmetric.
Step 2
The mean is same, i.e. $m=3.44$ million dollars and the standard error is,
$SE=\frac{8}{\sqrt{n}}$
$\frac{4.7}{\sqrt{30}}=0.8581$ milion dollars