# Differentiate. F(x)=1/(8x-5)

Differentiate.
$F\left(x\right)=\frac{1}{8x-5}$
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Tolamaes04
$F\left(x\right)=\frac{1}{8x-5}$
If you bring 8x-5 up from the denominator you can then rewrite the F(x) as
$F\left(x\right)=\left(8x-5{\right)}^{-1}$, this will make it easier todifferentiate.
Now, use the general power rule which is $\frac{d}{dx}\left[{u}^{n}\right]=n{u}^{n-1}\ast {u}^{\prime }$
So, ${F}^{\prime }\left(x\right)=-1\left(8x-5{\right)}^{-2}\ast 8=-8\left(8x-5{\right)}^{-2}=\frac{-8}{\left(8x-5{\right)}^{2}}$