the solid lies between planes perpendicular to the x-axis at x=-1 and x=1. the cross-sections perpendicular to the x-axisarea. circles whose diameters stretch from the curve y = − 1 1 + x 2 to the curve y = 1 1 + x 2 b. vertical squares whose base edges run along the same ends

Question

the solid lies between planes perpendicular to the x-axis at x=-1 and x=1. the cross-sections perpendicular to the x-axisarea. circles whose diameters stretch from the curve   y  =  −      1          1      +              x                  2                     to the curve   y  =      1          1      +              x                  2                    b. vertical squares whose base edges run along the same ends

suponeriq · Accepted Answer

Have you had the derivatives of inverse trigonometric functions yet?      d          d      x        [      tan          −      1        ⁡  (  x  )  ]  =      1          1      +              x                  2                    If so you can use the definition of the anti-derivative to deduce      d          d      x        [      tan          −      1        ⁡  (  x  )  ]  =      1          1      +              x                  2                      ⇒  ∫      1          1      +              x                  2                      d  x  =      tan          −      1        ⁡  (  x  )

the solid lies between planes perpendicular to the x-axis at x=-1 and x=1. the cross-sections perpendicular to the x-axis are a. circles whose diameters stretch from the curve y=-1/(sqrt(1+x^2)) to the curve y=1/(1+x^2) b. vertical squares whose base edges run along the same ends

Answered question

Answer & Explanation

New Questions in Trigonometry