Let a, b and c be a real numbers such that a>0, b<0 and c<0. Find the sign of each expression.a) -ab) bcc) a-bd) ab+ac

sodni3 2021-03-09 Answered

Let a, b and c be a real numbers such that a>0,b<0 and c<0. Find the sign of each expression.
a) -a
b) bc
c) a-b
d) ab+ac

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Expert Answer

Malena
Answered 2021-03-10 Author has 83 answers

(a) Here a>0 −a will be a negative number.
Thus, sign of -a is negative .
(b) It is known that product of two negative number will be positive.
As b<0 and c<0 bc>0.
Thus, sign of bc is positive.
(c) It is known that when a negative number is subtracted from a positive number, the resultant number will be positive.
Here a>0,b<0 ab>0.
Thus, sign of a-b is positive.
(d) Here
a>0,b<0 ab<0
a>0,c<0 ac<0
So ac and bc negative.
It is known that sum of two negative number will be negative.
Thus, ab+ac<0.
Thus, sign of ab+ac is .

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