# I am stuck here on this problem, it should be in the six stepts of quadratic equations. ax^2-2x-13=0; x^2+2x=13; 4x^2 +8x=52; 4x^2+8x+4=52+4; 4x^2+8x+4=56

I am stuck here on this problem, it should be in the six stepts of quadratic equations.
$a{x}^{2}-2x-13=0\phantom{\rule{0ex}{0ex}}{x}^{2}+2x=13\phantom{\rule{0ex}{0ex}}4{x}^{2}+8x=52\phantom{\rule{0ex}{0ex}}4{x}^{2}+8x+4=52+4\phantom{\rule{0ex}{0ex}}4{x}^{2}+8x+4=56$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

kamphundg4
Step 1
Standard form:
$a{x}^{2}+bx+c=0$
If a sign says -, that means the following number is negative.

Brenton Dixon
Step 1
For this Equation you must remember the Order of Operations, aka the pemdas rule.

Step 2
Solved
note: 2x is the same as $2{x}^{1}$