How fast it is after 2 seconds?

How long will it take if the final velocity is 25 m/s?

John Landry
2022-07-21
Answered

A ball was dropped from the window of a building, 33.5 meters above the ground

How fast it is after 2 seconds?

How long will it take if the final velocity is 25 m/s?

How fast it is after 2 seconds?

How long will it take if the final velocity is 25 m/s?

You can still ask an expert for help

Killaninl2

Answered 2022-07-22
Author has **20** answers

It is given that A ball was dropped from the window of a building, 33.5 meters above the ground.

We have to solve two subproblems.

-How fast it is after 2 seconds?

-How long will it take if the final velocity is 25 m/s?

Now, to find how fast it is after 2 seconds.

We must use Newton's first law of motion, hence we have

v=u+gt−−−−(1), where t=2 sec, $g=9.8\text{}m/se{c}^{2}$ ,initial velocity is u=0 m/sec, we have to find the final velocity v.

So, now we have

$v=0+9.8\times 2=19.6\text{}m/sec$

hence, after 2 seconds it is fast by 19.6 m/sec

To find how long will it take if the final velocity is 25 m/s.

here, we have to find the time t, we have the final velocity is v=25 m/sec

Since, initial velocity is u=0 m/sec

Again, using Newton's first law of motion, hence we have

v=u+gt−−−−(1), put values in equation(1), so we have

$25=0+9.8\times t\phantom{\rule{0ex}{0ex}}\Rightarrow t=259.8=2.55102040816\text{}seconds$

hence, it will take 2.55102040816 seconds to reach at final velocity of 25 m/sec

We have to solve two subproblems.

-How fast it is after 2 seconds?

-How long will it take if the final velocity is 25 m/s?

Now, to find how fast it is after 2 seconds.

We must use Newton's first law of motion, hence we have

v=u+gt−−−−(1), where t=2 sec, $g=9.8\text{}m/se{c}^{2}$ ,initial velocity is u=0 m/sec, we have to find the final velocity v.

So, now we have

$v=0+9.8\times 2=19.6\text{}m/sec$

hence, after 2 seconds it is fast by 19.6 m/sec

To find how long will it take if the final velocity is 25 m/s.

here, we have to find the time t, we have the final velocity is v=25 m/sec

Since, initial velocity is u=0 m/sec

Again, using Newton's first law of motion, hence we have

v=u+gt−−−−(1), put values in equation(1), so we have

$25=0+9.8\times t\phantom{\rule{0ex}{0ex}}\Rightarrow t=259.8=2.55102040816\text{}seconds$

hence, it will take 2.55102040816 seconds to reach at final velocity of 25 m/sec

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