Consider the following reaction in the vessel with a movable piston. X (g) + Y (g) → Z (s) For this reaction, ΔU = 286 J, the piston moves up, and the system absorbs 388 J of heat from its surroundings. (a) Does the system do work? (b) How much work?

agantisbz 2022-07-22 Answered
Consider the following reaction in the vessel with a movable piston. X ( g ) + Y ( g ) Z ( s )For this reaction, u = 286   J, the piston moves up, and the system absorbs 388 J of heat from its surroundings.(a) Does the system do work? (b) How much work?
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Answers (1)

grocbyntza
Answered 2022-07-23 Author has 25 answers
according to first law of thermodynamics
U = Q + W
here Uis channge in total internal energy of the system
Q is heat absorbed or released by system
W is work done on or by the system given that
U = 286   J Q = 388   J
W = U Q W = 286   J 388   J W = 102   J
thus
(a) work is done by the system
(b) value of work (W)=102 J
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