# As the atomic number Z increases, is the Hartree-Fock approximation getting better and better, or worse and worse?

As the atomic number $Z$ increases, is the Hartree-Fock approximation getting better and better, or worse and worse?
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Killaninl2
Hartree-Fock is less accurate for heavier atoms. There are more configurations and these are closer in energy to each other, so multiconfigurational Hartree-Fock (MCHF) is required. Relativistic effects become more important so the Dirac equation must be solved, in case you are referring to Schrödinger based Hartree-Fock.