# Distance between (5,-6,4) and (-6,3,4)?

Distance between (5,-6,4) and (-6,3,4)?
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Helena Howard
The distance between two points (in any dimension greater than or equal to 2), is given by the square root of the sum of the squares of the differences of the correspondant coordinates. It's easier to write it in formulas than in words: if the two points are $\left({x}_{1},{y}_{1},{z}_{1}\right)$ and $\left({x}_{2},{y}_{2},{z}_{2}\right)$, then the distance is
$\sqrt{{\left({x}_{1}-{x}_{2}\right)}^{2}+{\left({y}_{1}-{y}_{2}\right)}^{2}+{\left({z}_{1}-{z}_{2}\right)}^{2}}$
So, in your case,
$\sqrt{{\left(5+6\right)}^{2}+{\left(-6-3\right)}^{2}+{\left(4-4\right)}^{2}}=\sqrt{{11}^{2}+{\left(--\right)}^{2}}$
$=\sqrt{121+81}=\sqrt{202}$