Find derivative of trigonometric function y=(3(1-sin x))/(2cos x)

Tabansi 2021-02-08 Answered
Find derivative of trigonometric function y=3(1sinx)2cosx
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Expert Answer

pivonie8
Answered 2021-02-09 Author has 91 answers
Simplify the trigonometric function
y=3(1sinx)2cosx
y=32(1cosx(sinxcosx))
y=32(secxtanx){1cosx=secxandsinxcosx=tanx}
Derivative of trigonometric function:
y=32(secxtanx)
dydx=ddx(32(secxtanx))
dydx=32(ddx(secx)ddx(tanx))
dydx=32((secxtanx)sec2x){xdx(secx)=(secxtanx)andd(dx)(tanx)=sec2x}
The derivative of function is given below
dydx=32((secxtanx)sec2x)
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Jeffrey Jordon
Answered 2021-12-14 Author has 2064 answers

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