# Equation in a fraction - have I solved it right? I'm solving entrance maths example problems from a university. I solved this one: (2x-3)/5 - (4x+5)/3=8

Equation in a fraction - have I solved it right?
I'm solving entrance maths example problems from a university. I solved this one:
$\frac{2x-3}{5}-\frac{4x+5}{3}=8$
My solution was -104/14 but in the answer sheet it's -11. Am I wrong? If so why?
Edit: I did the following steps:
1.$3\left(2x-3\right)-5\left(4x+5\right)=8$
2.$6x-9-20x+25=120$
3.$-14x=104$
4.$x=-104/14$
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agyalapi60
You forgot parentheses around the numerator of the second fraction.
The calculations should look like:
$\frac{2x-3}{5}-\frac{4x+5}{3}=8\phantom{\rule{0ex}{0ex}}6x-9-\left(20x+25\right)=120\phantom{\rule{0ex}{0ex}}6x-9-20x-25=120\phantom{\rule{0ex}{0ex}}-14x-34=120\phantom{\rule{0ex}{0ex}}-14x=154\phantom{\rule{0ex}{0ex}}x=-11$

Kenya Leonard
Look at
$3\left(2x-3\right)-5\left(4x+5\right)=120\phantom{\rule{thickmathspace}{0ex}}⟺\phantom{\rule{thickmathspace}{0ex}}6x-9-20x-25=120$
$-5\left(4x+5\right)=-20x-25$; you added +25 instead of subtracting 25.