$-22{x}^{6}+4{x}^{33}y+{y}^{7}=-17$

and found it to be

$\frac{dy}{dx}}={\displaystyle \frac{132{x}^{5}-132{x}^{32}y}{4{x}^{33}+7{y}^{6}}$

Now, I am trying to find the equation of the tangent line to the curve at the coordinate (1,1). So I then plug both 1 in for x and y into the above equation and come up with

$\frac{0}{11}$

Now I go to solve

$y-y1=m(x-x1)$

getting

$y-1=0(x-1)$

resulting in $y=1$ and the equation to be $y=x+1$ for my final answer. Am I going about this in the correct manner?