(a) A car generator turns at 400 rpm when the engine is idling. Its 300-turn, 5.00 by 8.00 cm rectangular coil rotates in an adjustable magnetic field so that it can produce sufficient voltage even at low rpms. What is the field strength needed to produce a 24.0 V peak emf? (b) Discuss how this required field strength compares to those available in permanent and electromagnets.

Ruby Briggs 2022-07-23 Answered
(a) A car generator turns at 400 rpm when the engine is idling. Its 300-turn, 5.00 by 8.00 cm rectangular coil rotates in an adjustable magnetic field so that it can produce sufficient voltage even at low rpms. What is the field strength needed to produce a 24.0 V peak emf? (b) Discuss how this required field strength compares to those available in permanent and electromagnets.
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Answers (1)

nuramaaji2000fh
Answered 2022-07-24 Author has 18 answers
a The emf produced is given by
ϵ = N B A ω
For a given emf, it is clear that the needed field will have to be
B = ϵ N A ω
Let us now remember that since the area is a rectangle, we have A = a b. Also, to convert from rotations per minute to radians per second, we need to multiply by 2 π and divide by 60 - that is, multiplying by π 30 . This means that the final expression will be
Substituting numerically, we have
B = 30 ϵ a b N π r p m
b.This required field is quite high to be achieved by permanent magnets if the distance between them is considerable, and not as easy to be achieved by electromagnets either. Let us mention that the strongest electromagnets - those used in magnetic resonance imaging - usually produce fields no greater than 5 T.
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