Following function: Z=x^2+y^2, Z=x+y that i want to solve (to find the volume) with cylindrical coordinates.

valtricotinevh

valtricotinevh

Answered question

2022-07-22

Problem with finding the volume with cylindrical coordinates.
I have the following function:
Z = x 2 + y 2 ,   Z = x + y
that i want to solve (to find the volume) with cylindrical coordinates. I am evaluating the integral to get:
V = d V = R x 2 + y 2 x + y d z d A = R x + y ( x 2 + y 2 ) d A .
and from here i am trying to get the bounds for r by intersecting the two functions and i get that r = 0   o r   r = 1 therefore i tought that 0 r 1 but it dosen't seems right. But i get the following result:
2 π 0 1 ( r r 2 ) r d r d θ = 2 π ( r 3 3 r 4 4 ) | 0 1 = π 6
and this is not the corrent answer, i should get π 8 .. I know this is too specific to a given problem question i apologize for that but can someone tells me where i made a mistake

Answer & Explanation

decoratesuw

decoratesuw

Beginner2022-07-23Added 11 answers

Step 1
In cylindrical coordinates, you're after the volume of the region between z = r 2 and z = r ( cos ( θ ) + sin ( θ ) ) . Note that r 2 r ( cos ( θ ) + sin ( θ ) ) r cos ( θ ) + sin ( θ ) .
Step 2
So, you want to have cos ( θ ) + sin ( θ ) 0. That means that you have to compute π / 4 3 π / 4 0 cos ( θ ) + sin ( θ ) r 2 r ( cos ( θ ) + sin ( θ ) ) r d z d r d θ , which is indeed equal to π 8

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