Show that a=2i+2j+3k,b=3i+j−k,c=i−j−4k forms the sides of a triangle.

Alexandra Richardson 2022-07-22 Answered
Show that a = 2 i + 2 j + 3 k , b = 3 i + j k , c = i j 4 k forms the sides of a triangle.
My attempt: | a | = 17 , | b | = 11 , | c | = 18 . Since | c | < | a | + | b | using triangle inequality, we can say a,b,c form sides of a triangle.
I am not sure if my attempt is correct.
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Answers (1)

tun1t2j
Answered 2022-07-23 Author has 13 answers
In the vector form it is necessary to check the directions. By the triangle law of vector addition , the sum of vectors (in either of direction)should be zero. Then they are guaranteed to be sides of a triangle,then no need to check length or any other conditions. Also your method is not a proof. You can see here a + c = b or a + c + ( b ) = 0
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