You hear a sound at 65 dB. What is the sound intensity level if the intensity of the sound is doubled?

Question

Answer 1

Use the equation given by:

β = (10 d B) \log_{10} (\frac{I}{I_{0}})

If l is doubled, use a property of logarithms to get the new value of the intensity level,

β^{'}

. We have:

β^{'} = (10 d B) \log_{10} (\frac{2 I}{I_{0}}) (10 d B) [\log_{10} (2) + \log_{10} (\frac{I}{I_{0}})]

= (10 d B) \log_{10} 2 + β = 3 d B + 65 d B = 68 d B

Result:
68dB

Answers (1)