Assume that women's heights have a mean of 63 inches (5 feet 3inches) and a standard deviation of 3 inches. a. What women's height corresponds to a z-score of 1.20? b. What women's height corresponds to a z-score of negative −1.00?

kadejoset
2022-07-22
Answered

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bardalhg

Answered 2022-07-23
Author has **15** answers

a)Mean=63 inches

Standard deviation =3 inches

z-score=1.2

$\therefore $ z=(x-mean)/sd

$=(x-63)/3$

$1.2=\frac{x-63}{3}$

$\Rightarrow (1.2\ast 3)=x-63$

$\Rightarrow 3.6=x-63$

$\Rightarrow x=66.6$

Women`s corresponding to a z-score of 1.2 is 66.6 inches

Standard deviation =3 inches

z-score=1.2

$\therefore $ z=(x-mean)/sd

$=(x-63)/3$

$1.2=\frac{x-63}{3}$

$\Rightarrow (1.2\ast 3)=x-63$

$\Rightarrow 3.6=x-63$

$\Rightarrow x=66.6$

Women`s corresponding to a z-score of 1.2 is 66.6 inches

smuklica8i

Answered 2022-07-24
Author has **3** answers

b) Mean=63 inches

Standard devition =3 inches

z-score=-1.00

therefore

z=(x-mean)/sd

-1.00=(x-63)/3

-3.00=x-63

x=-3+63=60

Women`s height corresponds to a z-score of negative -1.00 is 60 inches

Standard devition =3 inches

z-score=-1.00

therefore

z=(x-mean)/sd

-1.00=(x-63)/3

-3.00=x-63

x=-3+63=60

Women`s height corresponds to a z-score of negative -1.00 is 60 inches

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