A particular sound wave can be graphed using the function y=-3sinx, how do you find the period of the function?

A particular sound wave can be graphed using the function $y=-3\mathrm{sin}x$, how do you find the period of the function?
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LitikoIDu6
For the case of a sound wave I would prefer to "see" it as a displacement along y as function of time. In general the form of the wave would be:
$y\left(t\right)=A\mathrm{sin}\left(\omega t\right)$ Function of t
where in your case you have:
$y\left(x\right)=-3\mathrm{sin}\left(1x\right)$ Function of x
although this may seem a bit strange and difficult it allows you to "see" the various components of your wave:
A is the amplitude or the maximum reached by the displacement of your wave that in your case is 3 (the minus tells you that at the start the sine wave will be "upside down" compared to a normal sine).
$\omega$ is a number that tells you the "speed" of your wave in terms of radians per seconds or:
$\omega =\frac{2\pi }{T}$ where T is the period.
In your case $\omega =1$ so that:
$\frac{2\pi }{T}=1$
and
$T=2\pi$ so that the period will be $2\pi$
We can "see" this wave graphically:
graph{$-3\mathrm{sin}\left(x\right)\left[-10,10,-5,5\right]$}