# How do I find the y intercept for P(x)=(x−1)^2(x−3)?

How do I find the y intercept for $P\left(x\right)=\left(x-1{\right)}^{2}\left(x-3\right)$?
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i4epdp
To get the $y$-intercept we basically set $x=0$. We thus get:
$\left(x-1{\right)}^{2}\left(x-3\right)⇒\left(-1{\right)}^{2}\left(-3\right)=-3$
Therefore the $y$-intercept is the point $\left(0,-3\right)$.
If you graph $\mathrm{P}\left(x\right)=\left(x-1{\right)}^{2}\left(x-3\right)$ you will see that it meets the 𝑦-axis at the point $\left(0,-3\right)$
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Bernard Boyer
Evaluate $P\left(0\right)$: That is, "plug in" $0$ everywhere you see $x$ in $P\left(x\right)$.
The value, when you evaluate, is your $y$ intercept.