makaunawal5
2022-07-17
Answered

How do I find the y intercept for $P(x)=(x-1{)}^{2}(x-3)$?

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i4epdp

Answered 2022-07-18
Author has **12** answers

To get the $y$-intercept we basically set $x=0$. We thus get:

$(x-1{)}^{2}(x-3)\Rightarrow (-1{)}^{2}(-3)=-3$

Therefore the $y$-intercept is the point $(0,-3)$.

If you graph $\mathrm{P}(x)=(x-1{)}^{2}(x-3)$ you will see that it meets the 𝑦-axis at the point $(0,-3)$

$(x-1{)}^{2}(x-3)\Rightarrow (-1{)}^{2}(-3)=-3$

Therefore the $y$-intercept is the point $(0,-3)$.

If you graph $\mathrm{P}(x)=(x-1{)}^{2}(x-3)$ you will see that it meets the 𝑦-axis at the point $(0,-3)$

Bernard Boyer

Answered 2022-07-19
Author has **5** answers

Evaluate $P(0)$: That is, "plug in" $0$ everywhere you see $x$ in $P(x)$.

The value, when you evaluate, is your $y$ intercept.

The value, when you evaluate, is your $y$ intercept.

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