Find the largest wavelength of light falling on double slits separated by $1.20\text{}\mu \text{}m$ for which there is a first-order maximum. Is this in the visible part of the spectrum?

Lillie Pittman
2022-07-18
Answered

Find the largest wavelength of light falling on double slits separated by $1.20\text{}\mu \text{}m$ for which there is a first-order maximum. Is this in the visible part of the spectrum?

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ab8s1k28q

Answered 2022-07-19
Author has **17** answers

Given:

Slit width, d = 1.2 micrometer = $1.2\times {10}^{-6}m$

order, m = 1

Formula used:

For the bright fringe, we use the formula

$d\mathrm{sin}\theta =m\lambda $

where, m is the number of order, d is the slit width, $\lambda $ is the wavelength and angle is the angular width.

For maximum value, the value of $\mathrm{sin}\theta =1$

So

$\lambda =1.2\times {10}^{-6}\text{}m$

This value of wavelength does not lie in the visible range. The visible range is from 400 nm to 700 nm.

Slit width, d = 1.2 micrometer = $1.2\times {10}^{-6}m$

order, m = 1

Formula used:

For the bright fringe, we use the formula

$d\mathrm{sin}\theta =m\lambda $

where, m is the number of order, d is the slit width, $\lambda $ is the wavelength and angle is the angular width.

For maximum value, the value of $\mathrm{sin}\theta =1$

So

$\lambda =1.2\times {10}^{-6}\text{}m$

This value of wavelength does not lie in the visible range. The visible range is from 400 nm to 700 nm.

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