Bernoulli's principle is an example of which law of thermodynamics. Explain why?

agantisbz
2022-07-18
Answered

Bernoulli's principle is an example of which law of thermodynamics. Explain why?

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nezivande0u

Answered 2022-07-19
Author has **16** answers

First law of thermodynamics is related to the conservation of energy.

As per energy conservation principle, the energy can not be created nor be destroyed but can convert from one form to another form. First law of thermodynamics also state the same principal of conservation of energy. The total heat input in cyclic process is equivalent to the work done during the process.

Bernoulli's theorem is also the conservation of mass and energy principle. Total energy of the fluid is in motion remains constant along the flow.

As per energy conservation principle, the energy can not be created nor be destroyed but can convert from one form to another form. First law of thermodynamics also state the same principal of conservation of energy. The total heat input in cyclic process is equivalent to the work done during the process.

Bernoulli's theorem is also the conservation of mass and energy principle. Total energy of the fluid is in motion remains constant along the flow.

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Consider the following reaction in the vessel with a movable piston.$X(g)+Y(g)\to Z(s)$For this reaction, $\mathrm{\u25b3}u=286\text{}J$, the piston moves up, and the system absorbs 388 J of heat from its surroundings.(a) Does the system do work? (b) How much work?

asked 2022-05-07

How to derive the formula for heat produced due to electricity correctly from Joule's laws for heating?

From Joule's laws, we get this:

$H\propto {I}^{2}Rt$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}H=K{I}^{2}Rt...(i)$

Now, we have to find/define the value of K. According to my book, when $1A$ of current passes through a conductor of $1\mathrm{\Omega}$ for $1s$, $1J$ heat is produced. If that's the case, then from $(i)$ we get this:

$1=K\times 1\times 1\times 1$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}K=1$

Therefore, we get our nice little formula:

$H=K{I}^{2}Rt$

My question with the above derivation is, how did we find that when $1A$ of current passes through a conductor of $1\mathrm{\Omega}$ for $1s$, $1J$ heat is produced? Through experimentation? What was the name of the experiment and who conducted it?

From Joule's laws, we get this:

$H\propto {I}^{2}Rt$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}H=K{I}^{2}Rt...(i)$

Now, we have to find/define the value of K. According to my book, when $1A$ of current passes through a conductor of $1\mathrm{\Omega}$ for $1s$, $1J$ heat is produced. If that's the case, then from $(i)$ we get this:

$1=K\times 1\times 1\times 1$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}K=1$

Therefore, we get our nice little formula:

$H=K{I}^{2}Rt$

My question with the above derivation is, how did we find that when $1A$ of current passes through a conductor of $1\mathrm{\Omega}$ for $1s$, $1J$ heat is produced? Through experimentation? What was the name of the experiment and who conducted it?

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The boiling point of water is measured four times. The results are 110.01°C, 110.02°C, 109.99°C, and 110.01°C. Which of the following statements best describes this measuring process?a) Accurate but not preciseb) Precise but not accuratec) Neither accurate nor precised) Both accurate and precise

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To determine:

The relationship of the boiling point and the altitude in the form of T=mx+b

The relationship of the boiling point and the altitude in the form of T=mx+b

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Rank the entropies of the following materials in an increasing order liquid Ag at 2435K, vapor Ag at 2435 K, solid Ag at 0K, solid Ag at 298 K, solid Ag 1234 K, and liquid Ag at 1234 K.

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Given thepartial differential forms $(\frac{\mathrm{\partial}A}{\mathrm{\partial}V}{)}_{T}=P$ and $(\frac{\mathrm{\partial}A}{\mathrm{\partial}T}{)}_{V}=-S$ what is the total differential of Helmholtz Free Energy in this case? Neglect all possible effects ofchemical potentials and assume that the process can occur.

A. $dA=-Tds-VdP$

B.$dA=-SdT+PdV$

C. $dA=SdT+PdV$

D. $dA=-PdS-SdV$

A. $dA=-Tds-VdP$

B.$dA=-SdT+PdV$

C. $dA=SdT+PdV$

D. $dA=-PdS-SdV$

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What conditions are necessary for the free-energy change to be used to predict the spontaneity of a reaction?