Emelia registers vehicles for the Department of Transportation. Sports utility vehicles (SUVs) make up 12% of the vehicles she registers. Let V be the number of vehicles Emelia registers in a day until she first registers an SUV. Assume the type of each vehicle is independent. Find the probability that Emelia registers more than 4 vehicles before she registers an SUV.

Cumulative geometric probability (greater than a value)
Emelia registers vehicles for the Department of Transportation. Sports utility vehicles (SUVs) make up 12% of the vehicles she registers. Let V be the number of vehicles Emelia registers in a day until she first registers an SUV. Assume the type of each vehicle is independent. Find the probability that Emelia registers more than 4 vehicles before she registers an SUV.
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Step 1
Each vehicle is selected at random, with probability of selecting an SUV being 0.12, since 12% of cars are SUVs. The geometric distribution gives the number of trials of "SUV or not SUV?", as you examine each car in turn, before the first SUV is found, so this occurs with probability .
In fact, it is better to use the "CDF of the geometric distribution", which says .
So, the probability of 4 trials or fewer before the first SUV is given by
so more than 4 vehicles is $1-0.40=0.60$.
Step 2
The fact you mention P(MORE than 4 vehicles BEFORE she registers an SUV) is equal to P(FIRST 4 cars not SUVs) is the idea of reversing the probability, so more than 4 is the negation of the event less than or equal to 4, so just do $P\left(\text{event occurs}\right)=1-P\left(\text{event does not occur}\right)$ which is why you go from 0.4 to $1-0.4=0.6$ after using the CDF.