# Use the Quadratic Formula to solve 8x^2 − 24x + 18 = 0.

Use the Quadratic Formula to solve $$\displaystyle{8}{x}^{{2}}−{24}{x}+{18}={0}.$$

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faldduE
$$\displaystyle{8}{x}^{{2}}−{24}{x}+{18}={0}$$
$$\displaystyle{4}{x}^{{2}}−{12}{x}+{9}={0}$$
We know that,
The standard quadratic equation is: $$\displaystyle{a}{x}^{{2}}+{b}{x}+{c}={0}$$
Quadratic formula is: $$\displaystyle{x}=\frac{{−{b}\pm\sqrt{{{b}^{{2}}−{4}{a}{c}}}}}{{{2}{a}}}$$
Here, a=4, b=−12, c=9
$$\displaystyle{x}={\left(-{\left(-{12}\right)}\pm\frac{\sqrt{{{\left(-{12}\right)}^{{2}}-{4}{\left({4}\right)}{\left({9}\right)}}}}{{{2}{\left({4}\right)}}}\right.}$$
$$\displaystyle{x}=\frac{{{12}\pm\sqrt{{{144}-{144}}}}}{{8}}$$
$$\displaystyle{x}=\frac{{12}}{{8}}$$
$$\displaystyle{x}=\frac{{3}}{{2}}$$