Does cancellation impact vertical asymptotes?

Question: Let $r(x)=\frac{({x}^{2}+x)}{(x+1)(2x-4)}$. Does the graph has x=1 as one of its asymptotes?

Answer: No.

My reasoning: $\frac{({x}^{2}+x)}{(x+1)(2x-4)}=\frac{x(x+1)}{(x+1)(2x-4)}=\frac{x}{(2x-4)}$ and so, it cannot have x=−1 as one of its asymptotes.

However, what if I don't calcel and then say that −1 is a vertical asymptote? Will I be wrong?

Question: Let $r(x)=\frac{({x}^{2}+x)}{(x+1)(2x-4)}$. Does the graph has x=1 as one of its asymptotes?

Answer: No.

My reasoning: $\frac{({x}^{2}+x)}{(x+1)(2x-4)}=\frac{x(x+1)}{(x+1)(2x-4)}=\frac{x}{(2x-4)}$ and so, it cannot have x=−1 as one of its asymptotes.

However, what if I don't calcel and then say that −1 is a vertical asymptote? Will I be wrong?