# Nuclear Mass and stabilityAg−109 Mass parabola putting the Atomic number on the x−axis and the Mass of the nuclei on the y−axis (calculated as M=Zm_p+(A−Z)m_n−B).

Nuclear Mass and stability. plotting the $Ag$$-109$ Mass parabola putting the Atomic number on the $x-$axis and the Mass of the nuclei on the $y-$axis (calculated as $M=Z{m}_{p}+\left(A-Z\right){m}_{n}-B$).
Noticed that even if the $Ag-109\left(Z=47\right)$ is the stable element the minimum of the parabola is on $Z=48$. Is that possible?
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Osvaldo Crosby
Yes, It is possible because the $Q$ value of the electron capture process from $48\to 47$ is ($M$ initial - M final + electron mass) and not ($M$ initial - $M$ final)