0.889

0.216

0.992

0.008

PoentWeptgj
2022-07-18
Answered

80% of YIC students play video or computer games. Choose 3 students at random. The e probability that at least one of 3 play video or computer game is

0.889

0.216

0.992

0.008

0.889

0.216

0.992

0.008

You can still ask an expert for help

Cheyanne Charles

Answered 2022-07-19
Author has **13** answers

n= 3

p= 0.8

$X\sim \text{Binom(n,p)}$

$P(X\ge 1)=1-P(X<1)$

$=1-P(X\le 0)$

= 1 - 0.0080 [Excel command: =BINOMDIST(x,n,p,true) ]

= 0.992

p= 0.8

$X\sim \text{Binom(n,p)}$

$P(X\ge 1)=1-P(X<1)$

$=1-P(X\le 0)$

= 1 - 0.0080 [Excel command: =BINOMDIST(x,n,p,true) ]

= 0.992

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For each of the following examples, state whether the chi-square goodness-of-fit or the chi-square test for independence is appropriate.

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B. test for independence

Any help

15a. An instructor tests whether class attendance (low, high) and grade point average (low, average, high) are independent.

A. goodness of fit test

B. test for independence

15b. An educator tests whether the teacher's speaking style (monotone, dynamic) and student interest (low, high) are independent.

A. goodness of fit test

B. test for independence

15c. A sports psychologist compares the number of athletes with Type A or Type B personality traits.

A. goodness of fit test

B. test for independence

Any help

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