Consider having 2-D Cartesian coordinate xy-plane, a block connected to a spring

Braylon Lester

Braylon Lester

Answered question

2022-07-19

Let's consider having 2-D Cartesian coordinate xy-plane, a block connected to a spring (placed horizontally on negative part of x-axis and having natural length L) sitting at the origin point with the spring at natural length.It is allowed to oscillate back and forth about the origin. From the equation that relates the work done by conservative force and the potential energy, U ( x a ) U ( x b ) = x b x a F x d x. If we define the zero point at x=0, we can express its potential energy for 0 < x < L, with
U ( x ) U ( x = 0 ) = 0 x k x d x U ( x ) = 1 2 k x 2
while for −L<x<0, we have (the restoring force switch sign as it now points to the positive x- direction):
U ( x ) U ( x = 0 ) = 0 x k x d x U ( x ) = 1 2 k x 2
My question: Is my idea and this approach for the energy of the system correct? Because I saw from some reference books, they simply say that it is just 1 2 k x 2 for both of the conditions.

Answer & Explanation

neobuzdanio

neobuzdanio

Beginner2022-07-20Added 13 answers

For L < x < 0, a spring force of + k x would point in the negative direction (since k>0 and x<0.) This would not be a restoring force, as it would point away from the origin.
On the other hand, a force of F = k x for all x points in the negative direction for positive x (F<0 and x>0), but points in the positive direction for negative x (F>0 and x<0). This is the correct function to model the force, and leads to a potential energy of 1 2 k x 2 for all x

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Force, Motion and Energy

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?