# If p(z) = (z-3)(z+4)(z-8) then find p(5)

If $p\left(z\right)=\left(z-3\right)\left(z+4\right)\left(z-8\right)$ then find $p\left(5\right)$
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Step 1
$p\left(z\right)=\left(z-3\right)\left(z+4\right)\left(z-8\right)$ then find $p\left(5\right)$
Let assume $z=1$;
Now put $z=1;p\left(1\right)=\left(1-3\right)\left(1+4\right)\left(1-8\right)=\left(-2\right)\left(5\right)\left(-7\right)=10$
Step 2
We have to find P(5) means $z=5$
for this put $z=5$ in the P(z).,
$P\left(5\right)=\left(5-3\right)\left(5+4\right)\left(5-8\right)=\left(2\right)\left(9\right)\left(-3\right)$
$P\left(5\right)=-54$
$\therefore P\left(5\right)=-54$