If a<x and b<y, then the rectangle with corners at (x,y), (x,0), (0,y), and (0,0) has an area greater than ab.

Shannon Andrews 2022-07-15 Answered
If a < x and b < y, then the rectangle with corners at (x,y), (x,0), (0,y), and (0,0) has an area greater than ab.
You can still ask an expert for help

Want to know more about Discrete math?

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (1)

repotasonwf
Answered 2022-07-16 Author has 12 answers
Step 1
What are the length of the sides of the rectangle? If you plot them, it will be easy to see that the lengths are x and y.
The area of a rectangle is base x height so the area of this rectangle is xy. We know a < x and b < y. Let x = a + α and y = b + β for some α and β positive real numbers. Then we substitute the area xy into ( a + α ) ( b + β ). Multiply this out and get that this is greater than ab.

We have step-by-step solutions for your answer!

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question