Solving the logarithimic inequality ${\mathrm{log}}_{2}\frac{x}{2}+\frac{{\mathrm{log}}_{2}{x}^{2}}{{\mathrm{log}}_{2}\frac{2}{x}}\le 1$

I tried solving the logarithmic inequality:

${\mathrm{log}}_{2}\frac{x}{2}+\frac{{\mathrm{log}}_{2}{x}^{2}}{{\mathrm{log}}_{2}\frac{2}{x}}\le 1$

several times but keeping getting wrong answers.

I tried solving the logarithmic inequality:

${\mathrm{log}}_{2}\frac{x}{2}+\frac{{\mathrm{log}}_{2}{x}^{2}}{{\mathrm{log}}_{2}\frac{2}{x}}\le 1$

several times but keeping getting wrong answers.