(a) \(\displaystyle{y}={b}_{{0}}+{b}_{{1}}{x}\)

where \(\displaystyle{b}_{{0}}\) is the y intercept

\(\displaystyle{b}_{{1}}\) is the slope

Slope = -0.75

y-intercept = -5

from the linear equation

\(\displaystyle{b}_{{0}}=-{5}\)

\(\displaystyle{b}_{{1}}=-{0.75}\)

(b) The slope is downward in graph. Because, the slope is negative value.

(c) Two point to graph:

where \(\displaystyle{b}_{{0}}\) is the y intercept

\(\displaystyle{b}_{{1}}\) is the slope

Slope = -0.75

y-intercept = -5

from the linear equation

\(\displaystyle{b}_{{0}}=-{5}\)

\(\displaystyle{b}_{{1}}=-{0.75}\)

(b) The slope is downward in graph. Because, the slope is negative value.

(c) Two point to graph: