I want to solve the following question: Let X(t) be the price of JetCo stock at time t years from the present. Assume that X(t) is a geometric Brownian motion with zero drift and volatility sigma=0.4/yr. If the current price of JetCo stock is 8.00 USD, what is the probability that the price will be at least 8.40 USD six months from now.

Stephanie Hunter

Stephanie Hunter

Answered question

2022-07-16

Probability of geometric Brownian motion
I want to solve the following question: Let X(t) be the price of JetCo stock at time t years from the present. Assume that X(t) is a geometric Brownian motion with zero drift and volatility σ = 0.4 / y r. If the current price of JetCo stock is 8.00 USD, what is the probability that the price will be at least 8.40 USD six months from now.
Here is my attempt: Since X(t) is a geometric Brownian motion, log(X(t)) is a regular Brownian motion with zero drift and σ = 0.4 / y r. We want to find the probability that log ( X ( 1 / 2 ) ) log ( 8.40 ) given that log ( X ( 0 ) ) = log ( 8.00 ).
What can I do from here?

Answer & Explanation

Jeroronryca

Jeroronryca

Beginner2022-07-17Added 13 answers

Step 1
You are on the right track so far, but you have the drift wrong. The drift of log(X(t)) is, from Ito's lemma, 1 2 σ 2 ..
After that you use the fact that since it's a brownian motion starting from log(8.0) the distribution is log ( X ( t ) ) N ( log ( 8 ) 1 2 σ 2 t , σ 2 t ) ..
Step 2
So let Z be normal with mean log ( 8 ) 1 2 σ 2 ( 1 2 ) and variance σ 2 ( 1 2 ) .. To finish the problem, you need to compute P ( Z > log ( 8.40 ) ) ..

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