Explain two features to distinguish between the interference pattern in Young double slit experiment

kadejoset 2022-07-15 Answered
A monochromatic light of wavelength 500 nm is incident normally on a single slit of width 0.2 mm to produce a diffraction pattern. Find the angular width of the central maximum obtained on the screen.
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Answers (1)

Hassan Watkins
Answered 2022-07-16 Author has 18 answers
The wavelength of incident light is given as λ = 500 × 10 9   m
The width of a single slit is given as a = 0.2 × 10 3   m
The angular width of central maxima is,
w = 2 λ a = 2 × 500 × 10 9 0.2 × 10 3 = 5 × 10 3 m
Thus, the angular width of the central maxima obtained on the screen is 5 mm.
Given the width of fringe in the young double-slit experiment is d = 0.5 × 10 3 m
Let there are n fringes made by a double-slit in the central maxima of the diffraction,
Then,
n = B B
where B = 2 λ D a is the width of central maxima in the diffraction and B = λ D d is the fringe width by the double slit.
Substituting the known values,
n = ( 2 λ D a ) ( λ D d ) = 2 λ D a × d λ D = 2 d a = 2 × 0.5 × 10 3 0.2 × 10 3 = 5
Thus, the number of fringes obtained is 5.
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