a) zero

b) more than 0 but less than 500 N

c) 500 N

d) more than 500 N

e) need more information

Explain with thorough reasoning.

Haley Madden
2022-07-17
Answered

Assume that you weigh 500 N. If you are falling down through the air at constant speed, the force of the air against your body is

a) zero

b) more than 0 but less than 500 N

c) 500 N

d) more than 500 N

e) need more information

Explain with thorough reasoning.

a) zero

b) more than 0 but less than 500 N

c) 500 N

d) more than 500 N

e) need more information

Explain with thorough reasoning.

You can still ask an expert for help

Arthur Gillespie

Answered 2022-07-18
Author has **10** answers

Step 1

According to the Newton's first law of motion,

A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.

Step 2

Assuming I weigh 500 N, I experience a downward gravitational force OAof 500 N.

If am falling down through the air at constant speed, then according to the Newton's first law of motion the net vertical force acting on me is zero. Therefore a force of the air of equal magnitude as the gravitational force (i.e. 500 N) is acting against body in opposite to the gravitational force.

Answer: c) 500 N

According to the Newton's first law of motion,

A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.

Step 2

Assuming I weigh 500 N, I experience a downward gravitational force OAof 500 N.

If am falling down through the air at constant speed, then according to the Newton's first law of motion the net vertical force acting on me is zero. Therefore a force of the air of equal magnitude as the gravitational force (i.e. 500 N) is acting against body in opposite to the gravitational force.

Answer: c) 500 N

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(a) What is the gravitational potential energy of the satellite-Earth system?

(b) What is the magnitude of the gravitational force exerted by the Earth on the satellite?

(c) What force does the satellite exert on the Earth?

(a) What is the gravitational potential energy of the satellite-Earth system?

(b) What is the magnitude of the gravitational force exerted by the Earth on the satellite?

(c) What force does the satellite exert on the Earth?

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A point mass m having charge q is connected with massless spring to a rigid wall on a horizontal surface.A horizontal uniform electric field E is switched on and mass is displaced through a distance x from equilibrium position.

Work done by electric force is $W=qE.x$ as electric force is constant.

But F(external) on spring mas system is equal to kx. So $W=kx.x=k{x}^{2}$ (equation 1) as external force i.e, electric force is constant.

We know that work done is stored in the form of potential energy and we know that potential energy stored in the spring is $1/2k{x}^{2}$.

So $W=1/2k{x}^{2}$ (let it be equation 2)

But the above 2 equations are not equal. From where did the 1/2 come from in the 2nd equation?

Work done by electric force is $W=qE.x$ as electric force is constant.

But F(external) on spring mas system is equal to kx. So $W=kx.x=k{x}^{2}$ (equation 1) as external force i.e, electric force is constant.

We know that work done is stored in the form of potential energy and we know that potential energy stored in the spring is $1/2k{x}^{2}$.

So $W=1/2k{x}^{2}$ (let it be equation 2)

But the above 2 equations are not equal. From where did the 1/2 come from in the 2nd equation?

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Find an expression for $T}_{1$, the tension in cable 1, that does not depend on $T}_{2$.

Express your answer in terms of someor all of the variables m,$\theta}_{1$, and $\theta}_{2$, as well as the magnitude of the acceleration due to gravity g.

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