Find the approximate temperature of a red star that emits light with a wavelength of maximum emission of 700 nm

equissupnica7
2022-07-17
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Dominique Ferrell

Answered 2022-07-18
Author has **18** answers

Wien's displacement law states that

$T=\frac{(2.9\times {10}^{-3})}{{\lambda}_{maximum}}$

where T is the temperature of the object,${\lambda}_{maximum}$ is the wavelength of emitted radiation of maximum intensity.

Given

Wavelength of maximum intensity radiation of the red star is $700\text{}nm=700\times {10}^{-9}\text{}m$

Henceforth the temperature can be calculated as

$T=\frac{(2.9\times {10}^{-3})}{700}\times {10}^{-9}\phantom{\rule{0ex}{0ex}}T=(\frac{2.9}{7})\times {10}^{-3-2+9}\phantom{\rule{0ex}{0ex}}T=4143\text{}K$

$T=\frac{(2.9\times {10}^{-3})}{{\lambda}_{maximum}}$

where T is the temperature of the object,${\lambda}_{maximum}$ is the wavelength of emitted radiation of maximum intensity.

Given

Wavelength of maximum intensity radiation of the red star is $700\text{}nm=700\times {10}^{-9}\text{}m$

Henceforth the temperature can be calculated as

$T=\frac{(2.9\times {10}^{-3})}{700}\times {10}^{-9}\phantom{\rule{0ex}{0ex}}T=(\frac{2.9}{7})\times {10}^{-3-2+9}\phantom{\rule{0ex}{0ex}}T=4143\text{}K$

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