1.$f(x)=\frac{x+1}{x-1}$

2. $f(x)=\frac{{x}^{2}-3x+4}{x+2}$

3. $\frac{\sqrt{x}-6}{\sqrt{x}+6}$

Glenn Hopkins
2022-07-16
Answered

Find the derivative of the functions by using the Quotient Rule. Simplify your answer.

1.$f(x)=\frac{x+1}{x-1}$

2. $f(x)=\frac{{x}^{2}-3x+4}{x+2}$

3. $\frac{\sqrt{x}-6}{\sqrt{x}+6}$

1.$f(x)=\frac{x+1}{x-1}$

2. $f(x)=\frac{{x}^{2}-3x+4}{x+2}$

3. $\frac{\sqrt{x}-6}{\sqrt{x}+6}$

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