Solve linear equation and check: 7x+3=6(x-1)+9

Solve linear equation and check: $7x+3=6\left(x-1\right)+9$

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Apply the distributive property to the right side of the equation as shown on the board
$a\left(b-c\right)=a×b-a×c$
$7x+3=6\left(x-1\right)+9$
$⇒7x+3=\left(6\right)\left(x\right)-\left(6\right)\left(1\right)+9$
$⇒7x+3=6x-6+9$
Evaluate the constant terms on the right side as shown on the board
$7x+3=6x+3$
Subtract 3 from both sides as shown on the board
$7x+3-3=6x+3-3$
Cancelling out +3 and -3 from both sides, we get the equation as shown on the board
$7x=6x$
Subtract 6x from both sides as shown on the board
$7x-6x=6x-6x$
Cancelling out 6x and -6x from the right side we get the equation as shown on the board
$7x-6x=0$
Subtracting 6x from 7x on the left side we get the final value of x as shown on the board
$x=0$
$x=0$