Find all values of x in the interval [0, 2pi] that satisfy the equation: 3cot^2 x=1

Ellen Chang 2022-07-16 Answered
Find all values of x in the interval [ 0 , 2 π ] that satisfy the equation:
3 cot 2 x = 1
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Answers (2)

karburitc
Answered 2022-07-17 Author has 7 answers
3 cot 2 x = 1
cot 2 x = 1 3
cot x = ± 1 3
cot x = ± 1 3
cos x sin x = ± 1 3
1 2 3 2 = 1 2 2 3 = 1 3
x = π 3 ; 3 π 3
2 π 3 ; 4 π 3
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Jeffrey Jordon
Answered 2022-08-01 Author has 2313 answers

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