Internal angle bisector of
, meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at P and the side AB at Q. If a, b, c represent the sides of
(c) The triangle
(d) AP is HM of b and c
My approach is as follow
This is the rough image that I have drawn
The official answer is a,b,c and d.
I am not able to approach from here